-4.905x^2+1.4x+29=0

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Solution for -4.905x^2+1.4x+29=0 equation: 



-4.905x^2+1.4x+29=0

a = -4.905; b = 1.4; c = +29;
Δ = b2-4ac
Δ = 1.42-4·(-4.905)·29
Δ = 570.94
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.4)-\sqrt{570.94}}{2*-4.905}=\frac{-1.4-\sqrt{570.94}}{-9.81}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.4)+\sqrt{570.94}}{2*-4.905}=\frac{-1.4+\sqrt{570.94}}{-9.81}
$

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